Considerando log 2 = t / 2 , assinale a alternativa que apr...

x = log (2/3 . 3/4 . 4/5 . 5/6 . 6/7 . 7/8 . 8/9 . 9/10)

x = log 1/5

x = log1 - log5 => log 1 - (log 10/2)

x = log1 - (log10 - log2)

x = 0 - (1 - log2)

x = log2 - 1

x = t/2 - 1

Gab - B

GAB: B -> x = t/2 - 1

Usando a propriedade dos logaritmos:

log (b · c) = log b + log c

x = log [(2/3)·(3/4)·(4/5)·(5/6)·(6/7)·(7/8)·(8/9)·(9/10)]

x = log [(2.3.4.5.6.7.8.9) / (3.4.5.6.7.8.9.10)]

x = log [(2.3.4.5.6.7.8.9) / (3.4.5.6.7.8.9.10)]

x = log(2/10)

x = log 2 - log 10

x = t/2-1